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19 votes
19 votes
Find C on line segment AB that is 2/5 the distance from A(0, 0) to B(10,20).

User Diabetesjones
by
2.9k points

1 Answer

21 votes
21 votes

In order to find the point C, which is located at 2/5 of the distance, we can calculate separately the x and y coordinates.

For the x-coordinate, the horizontal distance is the x-coordinate of the second point minus the x-coordinate of the first point:


10-0=10

Now we just need to find 2/5 of this distance:


(2)/(5)\cdot10=(20)/(5)=4

So the x-coordinate of the point C is 4.

Now, calculating the y-coordinate, the vertical distance is the y-coordinate of the second point minus the y-coordinate of the first point:


20-0=20

Now, calculating 2/5 of this distance, we have:


(2)/(5)\cdot20=(40)/(5)=8

So the y-coordinate of point C is 8.

Therefore the coordinates of point C are (4, 8)

User Mark K Cowan
by
3.3k points