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1 vote
Find the sum of the sequence 37+38+39+40+...130

2 Answers

2 votes

First, you have to calculate the number in the sequence

an = a+(n-1)d

130 = 27+(n-1)1

130-27 = n-1

103+1 = n

n = 104

Now, calculating for sum (Sn)

Sn = n/2 (a+an) = 104/2 (37+130) = 52 (167) = 8684

User Qwe
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5 votes
the sum is of37+38+39+40+...130 is 154.13
User Brunilda
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