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A ball is rolling down a hill. At one point near the top of the hill, its velocity is 2 m/s. Further down the hill, its velocity is 9 m/s. What is Δv?

User Johan Paul
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2 Answers

5 votes
7 m/s is your answer
User Ian Jamieson
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Answer:

+7 m/s

Step-by-step explanation:


\Delta v (change in velocity) is defined as the difference between the final velocity and the initial velocity:


\Delta v = v_f -v_i

where:


v_f = 9 m/s is the final velocity


v_i = 2 m/s is the initial velocity

Substituting the numbers into the equation, we find


\Delta v = 9 m/s - 2 m/s = +7 m/s

So, the ball has increased its velocity by 7 m/s.

User Wesley Van Opdorp
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