Question

If a = (0,0) and b = (6,3), whats a the length of ab

Answer 1

distance between 2 points, (x1,y1) and (x2,y2) is
D=
`√((x2-x1)^2+(y2-y1)^2)`
points (0,0) and (6,3)

D=
`√((6-0)^2+(3-0)^2)`
D=
`√((6-0)^2+(3-0)^2)`
D=
`√((6)^2+(3)^2)`
D=
`√(36+9)`
D=
`√(45)`
D=3√5

legnth of AB is 3√5

Answer 2

Length of ab is:

3√5

Explanation:

Distance(D) between 2 points, (x1,y1) and (x2,y2) is given by

D=
`√((x2-x1)^2+(y2-y1)^2)`

Here we have to find the distance between the points (0,0) and (6,3)

i.e. (x1,y1)=(0,0) and (x2,y2)=(6,3)

D=
`√((6-0)^2+(3-0)^2)`

D=
`√((6)^2+(3)^2)`

D=
`√(36+9)`

D=
`√(45)`

D=3√5

Hence, Length of ab is:

3√5