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2x − y = −4→10x − 5y = −20 3x 5y = 59→3x 5y = 59 13x = 39 which equation can replace 3x 5y = 59 in the original system and still produce the same solution? 2x – y = –4 10x – 5y = –20 7x = 39 13x = 39

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13x = 39 can replace 3x + 5y = 59 in the original system and still produce the same solution.
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