Question

The combustion of methane (CH4) with oxygen produces carbon dioxide,water, and energy. Calculate the totalmass of the reactants and theproducts for the following equationwhen 1 mol of CH4, reacts:CH4 + 202 → CO2 + 2H2O

Answer 1

Step-by-step explanation:

CH₄ + 2 O₂ ----> CO₂ + 2 H₂O

According to the coefficients of the reaction, when 1 mol of CH₄ reacts with 2 moles of O₂, 1 mol of CO₂ and 2 moles of H₂O are produced. We have to find the mass of each compound present in the reaction using their molar masses.

molar mass of C = 12.01 g/mol

molar mass of H = 1.01 g/mol

molar mass of O = 16.00 g/mol

molar mass of CH₄ = 1 * 12.01 g/mol + 4 * 1.01 g/mol

molar mass of CH₄ = 16.05 g/mol

molar mass of O₂ = 2 * 16.00 g/mol

molar mass of O₂ = 32.00 g/mol

molar mass of CO₂ = 1 * 12.01 g/mol + 2 * 16.00 g/mol

molar mass of CO₂ = 44.01 g/mol

molar mass of H₂O = 2 * 1.01 g/mol + 1 * 16.00 g/mol

molar mass of H₂O = 18.02 g/mol

If 1 mol of CH₄ is reacting we can find the number of moles of the other compounds using the coefficients of the reaction.

moles of CH₄ = 1 mol

moles of O₂ = 1 mol of CH₄ * 2 moles of O₂/(1 mol of CH₄)

moles of O₂ = 2 moles

moles of CO₂ = 1 mol of CH₄ * 1 mol of CO₂/(1 mol of CH₄)

moles of CO₂ = 1 mol

moles of H₂O = 1 mol of CH₄ * 2 moles of H₂O/(1 mol of CH₄)

moles of H₂O = 2 moles

And finally we can find the mass of each compound using the molar masses that we calculated before.

mass of CH₄ = 1 mol * 16.05 g/mol

mass of CH₄ = 16.05 g

mass of O₂ = 2 moles * 32.00 g/mol

mass of O₂ = 64.00 g

mass of CO₂ = 1 mol * 44.01 g/mol

mass of CO₂ = 44.01 g

mass of H₂O = 2 moles * 18.02 g/mol

mass of H₂O = 36.04 g

Answer:

mass of CH₄ = 16.05 g

mass of O₂ = 64.00 g

mass of CO₂ = 44.01 g

mass of H₂O = 36.04 g