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THE PRODUCT (x-10)(x+2) is equivalent to (1)x^2-20.....(2)2x-8..(3)x^2-8x+20 (4)x^2-8x+20...Explain

THE PRODUCT (x-10)(x+2) is equivalent to (1)x^2-20.....(2)2x-8..(3)x^2-8x+20 (4)x^2-8x+20...Explain
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THE PRODUCT (x-10)(x+2) is equivalent to

(1)x^2-20.....(2)2x-8..(3)x^2-8x+20
(4)x^2-8x+20...Explain

User Pirateofebay
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1 Answer

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You can use the FOIL method when you have two binomials. First, outer, inner, last
THE PRODUCT (x-10)(x+2) is equivalent to (1)x^2-20.....(2)2x-8..(3)x^2-8x+20 (4)x-example-1
User ZiggZagg
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