Question

What is the mass of the 3.7 mol PbO2
please explain

Answer 1

find the molar mass first
pb=207.2 and O=16
molar mass=(207.2∗1)+(16∗2)
=207.2+32 =239.2g/mol
mole= mass/molar mass
mass=mole∗molar mass
mass=3.7∗239.2
mass=885.0g

Answer 2

Answer : The mass of the 3.7 mole of
`PbO_2` is, 885.04 grams

Solution : Given,

Moles of
`PbO_2` = 3.7 moles

Molar mass of
`PbO_2` = 239.2 g/mole

Formula used :

`\text{Mass of }PbO_2=\text{Moles of }PbO_2* \text{Molar mass of }PbO_2`

Now put all the given values in this formula, we get the mass of
`PbO_2`

`\text{Mass of }PbO_2=(3.7moles)* (239.2g/mole)=885.04g`

Therefore, the mass of the 3.7 mole of
`PbO_2` is, 885.04 grams