3. When Tyler sees the peak in the mirror, angle of incidence " i " and angle of reflection " r " made by incident ray AE and reflected ray CE will be equal.
Now we can easily say ∠ r = ∠ C ( Alternate angles )
∠ i = ∠ A ( alternate angles)
Since ∠ i = ∠ r
Therefore, ∠ A = ∠ C
∠B = ∠D = 90°
and ∠ACB = ∠ECD
Hence ΔABC is similar to ΔEDC.
4. Corresponding sides of these similar triangles are AB and CD, BE and ED, AE and EC.