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What is the ph of 2.34 * 10^-5 naoh solution?
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What is the ph of 2.34 * 10^-5 naoh solution?

User Antara Datta
by
7.4k points

1 Answer

1 vote
NaOH = Na⁺ + OH⁻

pOH = - log [ OH⁻ ]

pOH = - log [ 2.34x10⁻⁵ ]

pOH = 4.63

Therefore:

pH + pOH = 14

pH + 4.63 = 14

pH = 14 - 4.63

pH = 9.37
User Nhydock
by
8.1k points
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