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How do you solve 1/4(b-8)^2=7?

User Daotoad
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1 Answer

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1/4 (b - 8)^2 = 7\\(b - 8)^2 = 7 * 4 = 28\\b - 8 = √(28)=2√(7)\\b = 8+2√(7)
User Nitgeek
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