Question

How do you solve 3log_3 4a=3?

Answer 1

3 log₃ 4a=3

1)a(log_b c)=log_b c^a
log₃(4a)³=3

2) log_a x=n ⇔ a^n=x
log₃ (4a)³=3 ⇔ 3³=(4a)³
27=64a³
a³=27/64
a=∛(27/64)
a=3/4

Answer: a=3/4