Question

Oliver tries to cut a piece of metal 30 centimeters long.The piece of metal ends up being 29.4 centimeterslong. What is the percent error in this situation?1.02%2%0.6%20%

Answer 1

Answer : Percentage error is 2%

`\begin{gathered} \text{The original length of the rod is 29. 4 cm} \\ \text{The expected length of the rod is 30 cm} \\ \text{Percentage error = }\frac{\exp ected\text{ length - original length}}{\text{original length}}\text{ x 100} \\ \text{Percentage error = }\frac{30\text{ - 29.4}}{29.4}\text{ x 100} \\ \text{Percentage error = }(0.6)/(29.4)\text{ x 100} \\ \text{Percentage error = 0.020 x 100} \\ \text{Percentage error = 2\%} \end{gathered}`