Question

What are the values of x in the equation 4x2 4x – 3 = 0? x = –1.5, 0.5 x = –0.5, –1.5 x = x =?

Answer 1

4x^2+ 4x – 3 = 0

Using Quadratic Formula:

x = [-4 + sqrt(16+48)]/8
or
x = [-4 - sqrt(16+48)]/8

Solving First equation:
x = [-4 + sqrt(16+48)]/8
= -4+8/8
= 0.5

Solving Second equation:
x = [-4 - sqrt(16+48)]/8
= - 4 - 8 /8
= -12/8
= -1.5

Answer 2

The values of x are

`x=-1.5\ , 0.5`

Explanation:

we have

`4x^(2)+4x-3=0`

Group terms that contain the same variable, and move the constant to the opposite side of the equation

`4x^(2)+4x=3`

Factor the leading coefficient

`4(x^(2)+x)=3`

Complete the square. Remember to balance the equation by adding the same constants to each side.

`4(x^(2)+x+.25)=3+1`

`4(x^(2)+x+.25)=4`

`(x^(2)+x+.25)=1`

Rewrite as perfect squares

`(x+0.5)^(2)=1`

Square root both sides

`x+0.5=(+/-)1`

`x=-0.5(+/-)1`

`x=-0.5+1=0.5`

`x=-0.5-1=-1.5`