Question

force of 50 N is applied to a 100 kg boulder, which starts at rest and moves 5.5 meters accross a level frictionless cliffside that is 12 meters high. How fast is the boulder moving when it leaves the cliff?

Answer 1

F = m*a => a = F/m = 50N / 100 kg = 0.5 m/s^2

Vf^2 = vo^2 + 2gd

Vf^2 = 0 + 2*9.8m/s^2 *5.5m =107.8 m^2 / s^2

Vf = 10.4 m/s