Question

What is the equivalent resistance for the resistors in the figure above?

Answer 1

We will have the following:

We calculate the equivalent resistance as follows:

First, we determine the two resistances in series, that is:

`R_1=6\Omega+10\Omega\Rightarrow R_1=16\Omega`

Now, using this we calculate the equivalent resistance in parallel:

`\begin{gathered} (1)/(R_2)=(1)/(16\Omega)+(1)/(4\Omega)\Rightarrow(1)/(R_2)=(5)/(16\Omega) \\ \\ \Rightarrow R_2=(16)/(5)\Omega\Rightarrow R_2=3.2\Omega \end{gathered}`

And finally, the total equivalent resistance will be given by the two remaining series:

`R_3=2\Omega+3.2\Omega\Rightarrow R_3=5.2\Omega`

So, the total equivalent resistance is 5.2 Ohms.