Question

How many grams are needed to obtain 1.5 moles of mgco3?

Answer 1

Molar mass MgCO3 => 84.31 g/mol

1 mole MgCO3 ----------- 84.31 g
1.5 moles MgCO3-------- ??

1.5 x 84.31 / 1 => 126.465 g

Answer 2

126 g

Step-by-step explanation:

A mole of a substance is the ratio of the mass of the substance to its molar mass.

Molar mass of a molecule is the sum of the atomic mass of the individual elements.

Molar mass of MgCO₃ = 24 + 12 + (16 x 3) = 84 g/mol

Given,

Moles = 1.5

Moles = mass / molar mass

Mass = moles x molar mass = 1.5 mol x 84 g/mol = 126 g