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Gregor Eesmaa · Answer 1 · 2017-04-10T18:46:57+0000

tn=n/2^(n+1) tn+1=(n+1)/2n+2=n/2n+2+1/2n+2 tn+1=tn/2+1/2n+2 t2=t1/2+1/2^3 t3=t2/2+1/2^4 . . . --------------------- adding Sn-t1=Sn/2 +(1/2^3+1/2^4+.........) Sn/2=t1+(1/2^3+1/2^4....)

Sn/2=1/4+(1/2^3)(1/(1-1/2)) =1/4+1/4 Sn=1

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