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Help!!! (143(5) + 67)5 ___________ 2 A. 1950 B. 1955 C. 1956 D. 1953
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Jun 27, 2017
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Help!!!
(143(5) + 67)5 ___________ 2
A.
1950
B.
1955
C.
1956
D.
1953
Mathematics
high-school
Pforhan
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Pforhan
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First multiply 143 and 5 to get 715. Add 715 and 67 to get 782. Multiply 782 and 5 to get 3910. Divide that by 2 to get B. 1955
Murat Yasar
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Jun 28, 2017
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Murat Yasar
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4
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1st up, we must use the (Order of operations) If you don't know what that is, then it is better known as PEMDAS.
(143(5) + 67)(5)
143 x 5 =715
(715 + 67)(5)
782 x 5 = 3910
The end product is 3,910
Hope this helps!
Jiri Mares
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Jul 3, 2017
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Jiri Mares
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