Question

A tire contains 1.50 mol of air at a gauge pressure of 205 kPa. If the volume of the air in the tire is 0.0120 m3, what is its temperature

Answer 1

197.07 K

Step-by-step explanation:

To solve this problem we can use the PV=nRT equation, where:

• P = 205 kPa ⇒ 205 * 0.00986 = 2.02 atm

• V = 0.0120 m³ ⇒ 0.0120 * 1000 = 12 L

• n = 1.50 mol

• R = 0.082 atm·L·mol⁻¹·K⁻¹

• T = ?

We input the data:

• 2.02 atm * 12 L = 1.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

• T = 197.07 K