Question

Please help asap...its not middle school math its high school math

Answer 1

`y=-16t^2\text{ + 400}`

Simplifying the above function

`y=-16(t^2-25\text{)}`

The axis of symmetry will be obtained when y = 0

`\begin{gathered} 0=-16(t^2-25\text{)} \\ \text{Dividing both sides by -16} \\ t^2\text{ - 25 = 0} \end{gathered}`
`\begin{gathered} t^2\text{ = 25} \\ t\text{ =}\sqrt[\square]{25} \\ \\ t\text{ =5} \end{gathered}`