Question

A bag comtains 2 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of choosing a blue marble, and without replacing it, drawing a green marble, and without replacing it, drawing another green marble.

A) 1/12
B) 5/12
C) 1/14
D) None of the above​

Answer 1

1 /14

Explanation:

P(B, G, G) =
`(3)/(9)` ·
`(4)/(8)` ·
`(3)/(7)`

=
`(1)/(3)` ·
`(1)/(2)` ·
`(3)/(7)`

=
`(1)/(14)`