Given:
Radiation emission in Cs atom = 9,192,632,770 cycles
To determine:
The wavelength of the above radiation
Step-by-step explanation:
It is given that :-
1 sec equivalent to 9,192, 631, 770
Now, frequency (ν) = cycles /sec = 9,192, 631, 770/sec
Wavelength of a radiation is given as:
λ = c/ν
where c = speed of light = 3*10⁸ m/s
λ = 3*10⁸ ms⁻¹/9,192, 631, 770 s⁻¹ = 0.0326 m
Ans: Thus the wavelength of this radiation is 0.033 m