Question

a boy is 24 years younger than his father. In 2 years time the sun of their ages will be 40. Find the present ages of father and son

Answer 1

Let the age of the boy be x.
Therefore the age of the father = x + 24. (The boy is 24 years younger implies that
his father is older by 24 years).

In 2 years time:
The boy will be = (x +2).
The father will be (x +24 +2) = (x + 26).

Sum of their ages = 40.
Therefore (x+2) + (x + 26) = 40.
x + x + 2 + 26 = 40
2x + 28 = 40
2x = 40 -28
2x = 12.
x = 12/2 = 6. x =6.
Present ages = x , x +24. = 6, (6 +24) = 6, 30.
Boy = 6 years old.
Father = 30 years old.
Cheers.

Answer 2

ooh fun

x=boy
y=father
x+24=y
(x+2)+(y+2)=40
subsitute x+24=y into equation
x+2+x+24+2=40
add like terms
2x+28=40
subtract 28 from both sides
2x=40
divide both sides by 2
x=son now=20
father=son+24
father=20+24=44

father=44
son=20