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A race car travels a circular track at an average rate of 135 mi/hr. The radius of the track is 0.450 miles. What is the centripetal acceleration of the car?

User Drmirror
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2 Answers

4 votes
135 * 135 / 0.450 = 40,500 mi/hr2

User Mmmdreg
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2 votes

Answer :
a_c=40500\ mi/h^2.

Explanation :

It is given that,

Velocity of a race car, v = 135 mi/hr

Radius of the track, r = 0.45 miles

We know that the centripetal acceleration is defined as :


a_c=(v^2)/(r)

r is the radius of the circle.


a_c=((135\ mi/hr)^2)/(0.45\ mi)


a_c=40500\ mi/h^2

So, the centripetal acceleration of the car is
a_c=40500\ mi/h^2.

Hence, this is the required solution.

User Nickgryg
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