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What is the solution set of the quadratic inequality 6x2+1<0

User Gented
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2 Answers

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minus 1 from both sides
6x^2<-1
divide both sides by 6
x^2<-1/6
take the square root of both sides
x<√(-1/6)
x<i√(1/6)

the solution is i√(1/6)
if you only consider real number, the solution set is empty
User Josh Hudnall
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3 votes

Answer:

Solution set of the quadratic equation is, Empty set

Explanation:

Given the quadratic equation:
6x^2+1>0

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract both sides by 1 we get;


6x^2+1-1>0-1

Simplify:


6x^2>-1

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 6 we get;


(6x^2)/(6) >(-1)/(6)

Simplify:


x^2>(-1)/(6)

For any x in real number there does not exist any number x which satisfy


x^2>(-1)/(6) , therefore, there is no solution for this set of the quadratic inequality or in other word we can say that set of the solution is Empty set.

User Dvsoukup
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