Question

A lawn mower runs on a mixture of gas and oil the ratio of ounces of gas to ounces of oil is 32 to 1 how many ounces of oil does the lawn mower need for 96 oounces of gas

Answer 1

Since the ratio of ounces of gas to oil is 32 to 1, we can solve the question by the rule of three.

`\begin{gathered} 32\rightarrow1 \\ 96\rightarrow x \end{gathered}`

Then

`\begin{gathered} x=(96\cdot1)/(32) \\ =(96)/(32) \\ =3 \end{gathered}`

Therefor, the lawn mower needs 3 ounces of oil.