Question

True or FalseIf an object is submerged in water, on earth, at a depth of 3km, the Pressure on the object is2.94 x 10^7 Pa

Answer 1

The pressure of a submerged object in a fluid is given by:

`P=\rho gh+P_(atm)`

where ρ is the density of the fluis, g is the acceleration of gravity, h is the depth of the object and Patm is the pressure of the atmosphere. In this case we know that:

• The density of water is 1000 kg/m^3

,

• The acceleration of gravity is 9.8 m/s^2

,

• The depth of the object is 3 km, that is, 3000 m.

,

• The atmospheric pressure is 101325 pascals.

Plugging these values in the equation given above we have:

`\begin{gathered} P=(1000)(9.8)(3000)+101325 \\ P=2.95*10^7 \end{gathered}`

Therefore, the pressure at this depth is 2.95x10^7 Pa.