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32 votes
32 votes
Solving equations by eliminationAlgebra

User Denis Sergeev
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1 Answer

17 votes
17 votes

Given the following question:


\begin{gathered} x-y=11 \\ 2x+y=19 \end{gathered}
\begin{gathered} x-y=11 \\ 2x+y=19 \\ x+2x=3x \\ -y+y=0 \\ 11+19=30 \\ 3x=30 \\ (3x)/(3)=x \\ (30)/(3)=10 \\ x=10 \\ \\ x-y=11 \\ x=10 \\ 10-y=11 \\ -y+10=11 \\ 10-10=0 \\ 11-10=1 \\ -y=1 \\ y=-1 \\ \end{gathered}

x = 10

y = -1

User Vito Ziv
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