Question

If A = 49 degrees, a = 32, and b = 28, find the measure of angle B. Round to the nearest tenth.

Answer 1

To find the angle B we can use the sin lay so we know that:

`(\sin(B))/(b)=(\sin (A))/(a)`

so for our triangle will be:

`(\sin(B))/(28)=(\sin (49))/(32)`

and we solve for B so:

`\begin{gathered} \sin (B)=(28\sin (49))/(32) \\ B=\sin ^(-1)(0.66) \\ B=41.3 \end{gathered}`