How much thermal energy is required to heat 15.2g of a metal (specific heat = 0.397 J/g * degrees celsius) from 21.0 degrees celsius to 40.3 degrees celsuis?

Question

asked Aug 25, 2017 162k views

2 Answers

Daniel Griscom · Answer 1 · 2017-08-31T22:22:33+0000

Answer: The amount of heat required is 116.5 Joules

Step-by-step explanation:

To calculate the amount of heat absorbed, we use the equation:

$q=m* C* \Delta T$

where,

q = amount of heat absorbed = ?

m = mass of metal = 15.2 g

C = specific heat capacity of metal =
0.397J/g^oC

$\Delta T$ = change in temperature =
(T_2-T_1)=(40.3-21.0)^oC=19.3^oC

Putting all the values in above equation, we get:

$q=15.2g* 0.397J/g^oC* 19.3^oC\\\\q=116.5J$

Hence, the amount of heat required is 116.5 Joules