Question

how much thermal energy is required to heat 15.2g of a metal (specific heat = 0.397 J/g * degrees celsius) from 21.0 degrees celsius to 40.3 degrees celsuis?

Answer 1

depends on the conducter

Answer 2

Answer: The amount of heat required is 116.5 Joules

Step-by-step explanation:

To calculate the amount of heat absorbed, we use the equation:

`q=m* C* \Delta T`

where,

q = amount of heat absorbed = ?

m = mass of metal = 15.2 g

C = specific heat capacity of metal =
`0.397J/g^oC`

`\Delta T` = change in temperature =
`(T_2-T_1)=(40.3-21.0)^oC=19.3^oC`

Putting all the values in above equation, we get:

`q=15.2g* 0.397J/g^oC* 19.3^oC\\\\q=116.5J`

Hence, the amount of heat required is 116.5 Joules