Question

A pumpkin is dropped after 5 seconds its velocity is 47m/s what is its acceleration

Answer 1

 9.81m/s Hope i helped

Answer 2

Acceleration,
`a=9.4\ m/s^2`

Step-by-step explanation:

It is given that,

Initial speed of the pumpkin, u = 0

Final speed of the pumpkin, v = 47 m/s

Time taken, t = 5 seconds

Acceleration of an object is given by :

`a=(v-u)/(t)`

`a=(47\ m/s)/(5\ s)`

`a=9.4\ m/s^2`

So, the acceleration of the pumpkin is
`9.4\ m/s^2`. Hence, this is the required solution.