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How many molecules are in 643.21 grams of Mg3(PO4)2?
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How many molecules are in 643.21 grams of Mg3(PO4)2?

User Nathan Kurz
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10 votes

Answer:

643.21g 1 mol 6.022^23

262.87 g 1 mol

= 1.4735E24 [Mg3(PO4)2]

User Vzzarr
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