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How many molecules are in 643.21 grams of Mg3(PO4)2?
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Feb 4, 2022
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How many molecules are in 643.21 grams of Mg3(PO4)2?
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Nathan Kurz
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Answer:
643.21g 1 mol 6.022^23
262.87 g 1 mol
= 1.4735E24 [Mg3(PO4)2]
Vzzarr
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Feb 10, 2022
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