How many molecules are in 643.21 grams of Mg3(PO4)2?

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asked Feb 4, 2022 177k views

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How many molecules are in 643.21 grams of Mg3(PO4)2?

Chemistry
high-school

Nathan Kurz asked

by Nathan Kurz

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Answer:

643.21g 1 mol 6.022^23

262.87 g 1 mol

= 1.4735E24 [Mg3(PO4)2]

Vzzarr answered Feb 10, 2022

by Vzzarr

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