Question

The sum of three numbers is 80. The first number is 8 more than the second. The third number is 2 times the second. What are the numbers?First number:Х?Second number:0Third number:

Answer 1

Let's use the variables x, y and z to represent each of the three numbers.

If the sum of the three numbers is equal to 80, we have our first equation:

`x+y+z=80`

The first number is 8 more than the second, so:

`x=y+8`

The third number is 2 times the second, so:

`z=2y`

Using these values of z and x in the first equation, let's solve it for y:

`\begin{gathered} (y+8)+y+(2y)=80 \\ 4y+8=80 \\ 4y=72 \\ y=18 \end{gathered}`

Now, calculating x and z, we have:

`\begin{gathered} x=18+8=26 \\ z=2\cdot18=36 \end{gathered}`

Therefore the first number is 26, the second number is 18 and the third number is 36.