Question

2 NaN3 -> 2Nat3 N2 Whatis the mole ratio of NaN3 to N22 How many grams of NaNa are needed to produce 144 grams of n2

Answer 1

Answer:Mass NaN3 = 222.73 grams

Explanations:

GIVEN:

• mass of N2 =, 144 g

,

• Molecular Mass N2 = ,28.02 g/mol

,

• Molecular Mass NaN3 = ,65,0099 g/mol

The balanced equation of the chemical reaction is given by :

`2NaN_3\Rightarrow\text{ 2Na+3N}_2`

(i) Calculate moles of N2

`\begin{gathered} Moles\text{ N2 = }\frac{Mass\text{ N}_2}{Molecular\text{ Mass N}_2} \\ \text{ =}(144g)/(28.02g)*mol \\ \text{ =5.14 moles N}_2 \end{gathered}`

This means that 5.14 moles are produced from NaN3

(ii) Determine moles and mass of NaN3 needed to produce 144 grams of N2.

by stoichiometry, we can see that :

• 2 Moles of NaN3 produces 3 moles N2

,

• X moles of NaN3 produces 5.14 moles N2

Therefore;

X Moles NaN3 =( 5.14 moles N2 *2 moles NaN3 )/ 3 moles N2

=3.43 moles of NaN3

Then ; Mass of NaN3 will be calculated as :

`\begin{gathered} Mass\text{ NaN}_3\text{= MolesNaN}_3\text{ * Molecular Mass NaN}_3\text{ } \\ \text{ = 3.43 moles * 65.0099g/mol} \\ \text{ =222.73 grams } \end{gathered}`

This means that Mass of NaN3 needed to produce 144g of N2 = 222.73 grams