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8. Solve the compound inequality.8x2-64 and 10x <60-8 < x <6-8 < x <6-82x≤6-8 < x≤6

8. Solve the compound inequality.8x2-64 and 10x <60-8 < x <6-8 < x &lt-example-1
User Mahen
by
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1 Answer

23 votes
23 votes

Answer:


-8\text{\operatorname{\leq}}\text{x}\lt\text{6}

Step-by-step explanation:

Here, we want to solve the given inequality

We proceed as follows:


\begin{gathered} 8x\text{ }\ge\text{ -64 and 10x }<\text{ 60} \\ x\text{ }\ge\text{ -}(64)/(8)\text{ and x}<\text{ }(60)/(10) \\ \\ x\ge\text{ -8 and x}<\text{ 6} \\ -8\text{ }\leq\text{ x}<\text{ 6} \end{gathered}

User Neil Steiner
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3.2k points
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