172k views
3 votes
Three consecutive odd integers have a sum of 33

User Haehn
by
8.0k points

2 Answers

2 votes
Let the odd integers be:

x, x + 2, x + 4 Since consecutive odd integers differ by 2.

Sum = 33

x + (x + 2) + (x + 4) = 33

x + x + 2 + x + 4 = 33

x + x + x + 2 + 4 = 33

3x + 6 = 33

3x = 33 - 6

3x = 27 Divide by 3

x = 27/3

x = 9

Recall the odd integers were, x, x + 2, x + 4

= 9, 9 + 2, 9 + 4

= 9, 11, 13

The three consecutive integers are 9, 11, & 13.

I hope this helps.
User Parth Verma
by
8.1k points
4 votes
Three consecutive integers that add up to 33 are 2 above and lower than a middle number.  This means that the average of these 3 numbers will be the same.  Therefore, 33/3=11 as the average.  Therefore 11 is the middle number, 9 is 2 below (a consecutive odd integer) and 13 is 2 above (a third consecutive odd integer).  Therefore the 3 numbers are 9, 11, and 13.
User Claviska
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.