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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).
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Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, -1).

User RKodakandla
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1 Answer

1 vote
Line:
3x+y=7
y=-3x+7

Slope of Perpendicular Line: 1/3x

For the perpendicular line to contain point (6,-1) the y-intercept would be (0,1), thus the equation of the line would be y=1/3x+1

y=1/3x+1

User Francesco Cristallo
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7.0k points
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