Answer:
50% green-seeded plants
Step-by-step explanation:
This is a typical monohybrid cross involving a single gene coding for seed color in pea plants. The allele for yellow seeds (Y) is dominant over the allele for green seeds (y) i.e. the allele Y will mask the expression of allele y in a heterozygous state.
A plant with heterozygous yellow seed i.e. have different alleles for the gene, will have the genotype Yy but phenotypically yellow-seeded since Y is dominant over y.
A plant with homozygous green seeds i.e. same alleles for the gene, will have a genotype (yy) since the green phenotype can only be expressed in a homozygous state.
Hence,in a cross between Yy and yy, each allele will separate into gametes according to Mendel's law of segregation. (See attached image).
The F1 offsprings as depicted in the image will have Yy, Yy, yy and yy genotypes.
Where 2 Yy: phenotypically yellow-seeded
2 yy: phenotypically green-seeded
Therefore, the percentage of F1 offsprings expected to have green seeds are: 2/4 × 100= 50%.