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What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b?

User Bated
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2 Answers

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F=-kx

F= - (4a) (3b)

F = -12ab

-kx

User Peter Keller
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Here is the correct answer of the given question above.
The restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b would be -12a/b.
It is solved using the formula F= -kx. Where x is the displacement and k is the spring constant. F = -(4a)(3b) and you get -12a/b. Hope this answer helps.
User Mendy
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