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1 vote
The difference of three times Faye's age and four times Joshua's age is 31. If Faye's age is five more than twice Joshua's age, how old is Faye?

User Polar
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1 Answer

6 votes
She is 31

F-Faye
J-Joshua

F3-J4=31
F=J2+5
(J2+5)(3)-J4=31
J2+5=31
J2+5-5=31-5
J2=26
J2/2=26/2
J=13

F=13(2)+5
F=26+5
F=31
User Gingemonster
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