42.3k views
4 votes
(1-sin^2x/cosx)= (sin2x/2sinx)

User Iakobski
by
7.8k points

1 Answer

2 votes
Left side:

1-sin²(x) = cos²(x)

1-sin²(x) / cos(x) = cos²(x) / cos(x) = cos(x)


Right side:

sin(2x) = 2 sin(x) cos(x)

sin(2x) / 2 sin(x) = 2 sin(x) cos(x) / 2 sin(x) = cos x
User Thomas Dickey
by
7.8k points

Related questions

asked Jan 19, 2017 197k views
ChrisMacSEA asked Jan 19, 2017
by ChrisMacSEA
7.5k points
1 answer
1 vote
197k views
asked Dec 15, 2019 159k views
Goppinath asked Dec 15, 2019
by Goppinath
7.6k points
1 answer
5 votes
159k views
asked May 12, 2019 172k views
Doxylee asked May 12, 2019
by Doxylee
8.1k points
1 answer
5 votes
172k views