Question

Al2(CO3)3 + 6HNO3 = 2Al(NO3)3 +3CO2 + 3H20

Is the net ionic equation this...

6H+ + Al(CO3)3 = 2Al3+ + 3CO2 + 3H2O

Answer 1

The net ionic equation for the reaction Al2(CO3)3 + 6HNO3 = 2Al(NO3)3 +3CO2 + 3H2O is 6H+ + Al(CO3)3 = 2Al3+ + 3CO2 + 3H2O.

The net ionic equation for the reaction Al2(CO3)3 + 6HNO3 = 2Al(NO3)3 +3CO2 + 3H2O is:

6H+ + Al(CO3)3 = 2Al3+ + 3CO2 + 3H2O

To obtain the net ionic equation, we cancel the spectator ions that appear on both sides of the equation, which in this case are the 6H+ and 6NO3-.

The net ionic equation shows only the ions that undergo a chemical change, which in this case are the 6H+ ions combining with the Al(CO3)3 compound to form 2Al3+ ions, CO2 gas, and 3H2O.

Answer 2

The first step is, as you have done, to write a properly balanced molecular equation, showing the states of reactants and products.
2 Al(NO3)3(aq) + 3 Na2CO3(aq) = Al2(CO3)3(s) + 6 NaNO3(aq)

Next step is to break up each reactant and product into the respective dissociated ions. But remember that, solids, gases and water are not taken as dissociating. Pay attention to the number of ions in each compound
2Al 3- (aq) + 6NO3- (aq) + 6Na-(aq) + 3CO3 2- (aq) → Al2(CO3)3(s) + 6Na+(aq) + 6NO3-(aq)
That is the full ionic equation. Note that Al2(CO3)3 being a solid precipitate does not ionise.
Writing net ionic equation:
Now Look at each ion on the reactant side and see if it is repeated exactly unchanged on the product side:
2Al3-(aq) as an example, does not appear on the products side. Keep it.
6NO3- (aq) does appear exactly as 6NO3- on the products side - delete it on both sides.
Continue this for all the reactants side. You will be left with the NET IONIC EQUATION
2Al 3- (aq) + 3CO3 2- (aq) → Al2(CO3)3(s)
That is the net ionic equation.
The ions which are common to both sides are spectator ions, they have not taken part in any reaction, so they are eliminated from the net ionic equatio