Question

A swimming pool has to be drained for maintenance. The pool is shaped like a cylinder with a diameter of and a depth of . Suppose water is pumped out of the pool at a rate of per hour. If the pool starts completely full, how many hours will it take to empty the pool?Use the value for , and round your answer to the nearest hour. Do not round any intermediate computations.

Answer 1

Given the following about rhe cylindrical pool:

Diameter = 9 m

Depth = 1.2 m

Suppose water is pumped out of th pool at the rate of 11 m per hour.

We are to take π as 3.14

First we we have to calculte the volume of the pool.

To calculate the volume of the pool, we will have to use the volume of the cylinder formula:

Volume = πr²h

Where:

r = Diameter/2 = D/2 = 9/2 = 4.5

r = 4.5 m

depth = height = 1.2 m

let's input into the formula:

Volume = 3.14 * 4.5² * 1.2

Volume = 3.14 * 20.25 * 1.2

Volume = W76.302 m³

Therefore, the pool holds 76.302 m³ of water.

At the rate of 11 m³ per hour:

(76.302 m³)/(11 m³/hr)

= 6.93654545

= 7 hrs (rounded to the nearest hour).