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Solve the following system of equations by elimination.

5x+2y=10
4x+3y=15

2 Answers

6 votes

Answer:

(0, -5)

Explanation:

Elimination method: Part one Y

5x - 2y = 10

4x - 3y = 15

Let's isolate y and we will multiply the first equation by -4 and the second by 5

-20x + 8 = -40

20x - 15y = 75

-7y = 35, divide both sides by -7 y

y = -5

Elimination method: Part two X

Since we cannot eliminate y right away, let's multiply the first expression by -3 and the second one by 2

-15x + 6y = -30

6x - 6y = 30

Now we have to solve it for x

-9x = 0

divide both sides by the coeficient

x = 0

0, -5 is the answer. Let's check!

5(0) - 2(-5) = 10 -2(-5) equals 10=10 which is correct!

4(0) - 3(-5) = 15 -3(-5) which is 15 = 15 which is correct!

User Dianna
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7.7k points
4 votes
5x+2y=10 4x+3Y=15 - - - ----------------- X-Y= -5 So,x= -5 And y =5
User Sandeep Parish
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8.0k points