Question

What is the mass of 52.3 L of Fe203Round your masses to whole numbers and give your answers with the correct number of sig figs and units.

Answer 1

They give us the volume of the substance, to calculate the mass we can relate the property of density which is equal to:

`\rho=(M)/(V)`

Where,

M is the mass of the substance

V is the volume

The density of Fe2O3 can be found in the table of properties of substances. At standard conditions, the density is equal to: 5.242 g/cm3.

The mass will be:

`\begin{gathered} \rho=(M)/(V) \\ M=\rho* V \\ M=5.242(g)/(cm3)*52.3L*(1000cm^3)/(1L)=274156.6g=274.2Kg \end{gathered}`

So, the mass of 52.3L of Fe2O3 is 274.2 Kg