Answer:
a. (P, L, W) = (32, 2, 14) . . . meters
b. (P, L, W) = (58, 1, 28) . . . meters
c. (P, L, W) = (22, 4, 7) . . . meters
d. 28 m²
Explanation:
a.
The perimeter of the rectangle is found on the vertical scale at the horizontal line through the point on the vertical line for length = 2 m. The width of the rectangle is found at the other point on that horizontal line.
Perimeter: 32 m
length: 2 m
width: 14 m
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b.
The greatest perimeter represented on the graph is the top line on which points are plotted. It is 58 meters. The two points on that perimeter line are lengths of 1 and 28 meters.
The rectangle with the largest perimeter shown on the graph has ...
Perimeter: 58 meters
length: 1 meter
width: 28 meters
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c.
The least perimeter represented on the graph is 22 m. The dimensions shown on that line are 4 m and 7 m.
Perimeter: 22 m
length: 4 m
width: 7 m
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d.
The fixed area is the product of length and width shown on any given perimeter line:
1×28 = 2×14 = 4×7 = 28 . . . square meters
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Additional comments
This is all about reading and understanding a graph. As with many graphs, not every grid line is marked, and not every point is on a grid line. That means you need to use your skill at interpolation to determine the coordinates of any given point.
You also need to realize that the two "length" dimensions shown on any given perimeter line are the length and width of the rectangle. Either could be called "length" and the other could be called "width." We took our cue from the first question, which claimed a length of 2 meters. That is, we called the shorter dimension "length" to match the wording in that part of the problem statement.