Question

What is the y-intercept of the equation of the line that is perpendicular to the line y =3/5 x 10 and passes through the point (15, –5)?the equation of the line in slope-intercept form is y =-5/3 x

Answer 1

I hope this helps you

Answer 2

The y-intercept of the equation of the line is 20.

Explanation:

The equation of given line is

`y=(3)/(5)x+10`

It is a slope intercept form of a line (y=mx+b), where m is slope and b is y-intercept.

The slope of the line is

`m_1=(3)/(5)`

The product of slopes of two perpendicular lines is -1.

`m_1* m_2=-1`

`(3)/(5)* m_2=-1`

`m_2=-(5)/(3)`

The slope of required line is
`-(5)/(3)` and it is passing through the point (15,-5).

The point slope form of a line is

`y-y_1=m(x-x_1)`

`y-(-5)=-(5)/(3)(x-15)`

`y+5=-(5)/(3)(x)+25`

`y=-(5)/(3)(x)+20`

The slope intercept form of required line is
`y=-(5)/(3)(x)+20`.

Therefore y-intercept of line is 20.