Question

The product of some negative number and 10 less than three times that number is 8 . find the num

Answer 1

-x(3x-10)=8
-3x^2+10x=8 (DISTRIBUTE)
-3x^2+10x-8=0 (BALANCE TO ZERO)
(-3x+4)(x-2)=0 (FACTOR)
(-x+4/3)(x-2)=0 (SIMPLIFY)
{x=2 OR x= 4/3}