Question

Someone please help me on this I'm unsure if my answer is correct

Answer 1

A. length = 23 cm; width = 5 cm

Explanation:

So if 4 times the width would be
`4w` and 3 more than would be
`+ 3`, the equation would be
`l = 4w + 3`. If the perimeter is 56, then the new equation,
`2(4w + 3) + 2(w) = 56` can be formed. This simplifies to
`8w + 6 + 2w = 56`, then to
`10w + 6 = 56`, then to
`10w = 50`, and finally,
`w = 5`. So the width is 5, and now plug it into the first equation.

`l = 4(5) + 3`, becomes
`l = 20 + 3`, becomes
`l = 23`.

So the dimensions are: length = 23 cm, width = 5 cm.

*And just to be sure,
`2(23 + 5) = 2(28) = 56` which is correct.